2.45x^2+0.001x=10

Solution for 2.45x^2+0.001x=10 equation:

2.45x^2+0.001x=10

We move all terms to the left:

2.45x^2+0.001x-(10)=0

a = 2.45; b = 0.001; c = -10;
Δ = b2-4ac
Δ = 0.0012-4·2.45·(-10)
Δ = 98.000001
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.001)-\sqrt{98.000001}}{2*2.45}=\frac{-0.001-\sqrt{98.000001}}{4.9}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.001)+\sqrt{98.000001}}{2*2.45}=\frac{-0.001+\sqrt{98.000001}}{4.9}
$